Heat Exchanger Design Calculator Documentation
Note: This documentation is based on standard chemical engineering principles for heat exchanger design. The actual implementation in the code may vary.
1. Objective
The Heat Exchanger Design Calculator is a tool for the preliminary thermal design of a shell-and-tube heat exchanger. It calculates the required heat transfer area, heat duty, and outlet temperatures based on the Log Mean Temperature Difference (LMTD) method.
2. Design Basis & Methodology
The core of the calculator is the LMTD method for heat exchanger analysis.
Key Formulas:
Heat Duty (Q): The rate of heat transferred from the hot fluid to the cold fluid.
Q = m_hot * Cp_hot * (T_hot_in - T_hot_out) Q = m_cold * Cp_cold * (T_cold_out - T_cold_in)Log Mean Temperature Difference (LMTD): The effective average temperature difference between the two fluids.
LMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2)Where
ΔT1andΔT2are the temperature differences at the two ends of the exchanger. A correction factor (Ft) is applied for multi-pass configurations.Required Heat Transfer Area (A): The fundamental design equation.
Q = U * A * LMTD * FtWhere
Uis the Overall Heat Transfer Coefficient.
3. Input Parameters
- Fluid Properties: Flow rates, specific heats (
Cp), and inlet temperatures for both the hot and cold streams. - Overall Heat Transfer Coefficient (U): An estimated or known value representing the overall thermal conductivity of the exchanger, including fouling.
- Exchanger Configuration: To determine the LMTD correction factor (
Ft).
4. Output Results
- Heat Duty (Q): The total heat transferred.
- Outlet Temperatures: The final temperatures of the hot and cold streams.
- LMTD: The Log Mean Temperature Difference.
- Required Heat Transfer Area (A): The surface area needed to achieve the heat duty.
5. Limitations and Assumptions
- The Overall Heat Transfer Coefficient (
U) is a critical input and is often an estimate. Its accuracy directly impacts the calculated area. - Assumes constant specific heats and
Uvalue across the temperature range. - Does not perform pressure drop calculations, which are a critical part of the mechanical design.
6. Example Calculation
Goal: Find the required area for a counter-current heat exchanger to cool a hot water stream.
Given:
- Hot Fluid (Water):
m_hot= 10 kg/s,Cp_hot= 4.18 kJ/kg·K,T_hot_in= 90°C,T_hot_out= 50°C - Cold Fluid (Oil):
m_cold= 15 kg/s,Cp_cold= 2.1 kJ/kg·K,T_cold_in= 20°C - Overall Heat Transfer Coefficient (U): 300 W/m²·K
- Configuration: Counter-current flow (
Ft= 1.0)
Calculation Steps:
Calculate Heat Duty (Q):
Q = m_hot * Cp_hot * (T_hot_in - T_hot_out) = 10 kg/s * 4.18 kJ/kg·K * (90 - 50) K = 1672 kWCalculate Cold Fluid Outlet Temperature (T_cold_out):
Q = m_cold * Cp_cold * (T_cold_out - T_cold_in)1672 kW = 15 kg/s * 2.1 kJ/kg·K * (T_cold_out - 20°C)T_cold_out = (1672 / (15 * 2.1)) + 20 = 53.08 + 20 = 73.08°CCalculate Log Mean Temperature Difference (LMTD):
ΔT1 = T_hot_in - T_cold_out = 90 - 73.08 = 16.92°CΔT2 = T_hot_out - T_cold_in = 50 - 20 = 30°CLMTD = (ΔT1 - ΔT2) / ln(ΔT1 / ΔT2) = (16.92 - 30) / ln(16.92 / 30) ≈ 22.84°CCalculate Required Heat Transfer Area (A):
Q = U * A * LMTD * Ft1,672,000 W = 300 W/m²·K * A * 22.84 K * 1.0A = 1,672,000 / (300 * 22.84) ≈ 244 m²
Result: A heat transfer area of approximately 244 m² is required.
Reference Standards
- TEMA Standards: Tubular Exchanger Manufacturers Association (9th Edition).
- ASME Section VIII Div 1: Rules for Construction of Pressure Vessels.
- API Standard 660: Shell-and-tube Heat Exchangers for General Refinery Services.